-3w^2-2w+8=0

Solution for -3w^2-2w+8=0 equation:

-3w^2-2w+8=0

a = -3; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-3}=\frac{-8}{-6}
=1+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-3}=\frac{12}{-6}
=-2
$